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130025431201 = 267148680431
BaseRepresentation
bin111100100011000011…
…1101010000010100001
3110102121200210021200011
41321012013222002201
54112243002244301
6135422144124521
712252102633541
oct1710607520241
9412550707604
10130025431201
1150163a69a56
1221249306741
13c35223a093
146416a09321
1535b01d8a51
hex1e461ea0a1

130025431201 has 4 divisors (see below), whose sum is σ = 130074114304. Its totient is φ = 129976748100.

The previous prime is 130025431187. The next prime is 130025431301. The reversal of 130025431201 is 102134520031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130025431201 - 213 = 130025423009 is a prime.

It is a super-2 number, since 2×1300254312012 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130025431301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24337545 + ... + 24342886.

It is an arithmetic number, because the mean of its divisors is an integer number (32518528576).

Almost surely, 2130025431201 is an apocalyptic number.

It is an amenable number.

130025431201 is a deficient number, since it is larger than the sum of its proper divisors (48683103).

130025431201 is an equidigital number, since it uses as much as digits as its factorization.

130025431201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48683102.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 130025431201 its reverse (102134520031), we get a palindrome (232159951232).

The spelling of 130025431201 in words is "one hundred thirty billion, twenty-five million, four hundred thirty-one thousand, two hundred one".

Divisors: 1 2671 48680431 130025431201