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130051325201300 = 22521300513252013
BaseRepresentation
bin11101100100011111101111…
…000010101000101110010100
3122001110210012110102122211022
4131210133233002220232110
5114021230103222420200
61140332430511100312
736251620034546036
oct3544375702505624
9561423173378738
10130051325201300
1138490503710668
1212704999811698
135774a30a44899
1424187368cdc56
151007e0045a885
hex7647ef0a8b94

130051325201300 has 18 divisors (see below), whose sum is σ = 282211375687038. Its totient is φ = 52020530080480.

The previous prime is 130051325201299. The next prime is 130051325201309. The reversal of 130051325201300 is 3102523150031.

It can be written as a sum of positive squares in 3 ways, for example, as 336810765316 + 129714514435984 = 580354^2 + 11389228^2 .

It is a super-2 number, since 2×1300513252013002 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130051325201300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130051325201309) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 650256625907 + ... + 650256626106.

It is an arithmetic number, because the mean of its divisors is an integer number (15678409760391).

Almost surely, 2130051325201300 is an apocalyptic number.

130051325201300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130051325201300 is an abundant number, since it is smaller than the sum of its proper divisors (152160050485738).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130051325201300 is a wasteful number, since it uses less digits than its factorization.

130051325201300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1300513252027 (or 1300513252020 counting only the distinct ones).

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 130051325201300 its reverse (3102523150031), we get a palindrome (133153848351331).

The spelling of 130051325201300 in words is "one hundred thirty trillion, fifty-one billion, three hundred twenty-five million, two hundred one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 1300513252013 2601026504026 5202053008052 6502566260065 13005132520130 26010265040260 32512831300325 65025662600650 130051325201300