Base | Representation |
---|---|
bin | 10010111011111100110… |
… | …101111001110101001011 |
3 | 11121101221101010201101112 |
4 | 102323330311321311023 |
5 | 132310101430043311 |
6 | 2433452533040535 |
7 | 163005655306313 |
oct | 22737465716513 |
9 | 4541841121345 |
10 | 1301322112331 |
11 | 46198445280a |
12 | 19025618614b |
13 | 95938ca5127 |
14 | 46dacdc4443 |
15 | 23cb503228b |
hex | 12efcd79d4b |
1301322112331 has 2 divisors, whose sum is σ = 1301322112332. Its totient is φ = 1301322112330.
The previous prime is 1301322112327. The next prime is 1301322112339. The reversal of 1301322112331 is 1332112231031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1301322112331 - 22 = 1301322112327 is a prime.
It is a super-2 number, since 2×13013221123312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1301322112297 and 1301322112306.
It is not a weakly prime, because it can be changed into another prime (1301322112339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650661056165 + 650661056166.
It is an arithmetic number, because the mean of its divisors is an integer number (650661056166).
Almost surely, 21301322112331 is an apocalyptic number.
1301322112331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301322112331 is an equidigital number, since it uses as much as digits as its factorization.
1301322112331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1301322112331 its reverse (1332112231031), we get a palindrome (2633434343362).
The spelling of 1301322112331 in words is "one trillion, three hundred one billion, three hundred twenty-two million, one hundred twelve thousand, three hundred thirty-one".
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