Base | Representation |
---|---|
bin | 11101100101110011100001… |
… | …111110001110010101000111 |
3 | 122001210101102222100220201102 |
4 | 131211303201332032111013 |
5 | 114024213340331112043 |
6 | 1140442031000450315 |
7 | 36261253512100022 |
oct | 3545634176162507 |
9 | 561711388326642 |
10 | 130141300254023 |
11 | 38515685242473 |
12 | 1271a30a17999b |
13 | 578036c640956 |
14 | 241cc303761b9 |
15 | 100a41950a6b8 |
hex | 765ce1f8e547 |
130141300254023 has 16 divisors (see below), whose sum is σ = 132650398103040. Its totient is φ = 127659471652416.
The previous prime is 130141300254013. The next prime is 130141300254061. The reversal of 130141300254023 is 320452003141031.
It is a cyclic number.
It is not a de Polignac number, because 130141300254023 - 220 = 130141299205447 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130141300254013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5663615 + ... + 17098512.
It is an arithmetic number, because the mean of its divisors is an integer number (8290649881440).
Almost surely, 2130141300254023 is an apocalyptic number.
130141300254023 is a deficient number, since it is larger than the sum of its proper divisors (2509097849017).
130141300254023 is a wasteful number, since it uses less digits than its factorization.
130141300254023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22762726.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 130141300254023 its reverse (320452003141031), we get a palindrome (450593303395054).
The spelling of 130141300254023 in words is "one hundred thirty trillion, one hundred forty-one billion, three hundred million, two hundred fifty-four thousand, twenty-three".
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