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13031214143 = 36931352853
BaseRepresentation
bin11000010001011100…
…01000110000111111
31020122011112021012212
430020232020300333
5203141442323033
65553024051035
7640632330653
oct141056106077
936564467185
1013031214143
115587865072
122638163a7b
1312c89b04cc
148b8972a63
1551406a748
hex308b88c3f

13031214143 has 4 divisors (see below), whose sum is σ = 13031603928. Its totient is φ = 13030824360.

The previous prime is 13031214139. The next prime is 13031214151. The reversal of 13031214143 is 34141213031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34141213031 = 191796905949.

It is a cyclic number.

It is not a de Polignac number, because 13031214143 - 22 = 13031214139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13031214103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139496 + ... + 213357.

It is an arithmetic number, because the mean of its divisors is an integer number (3257900982).

Almost surely, 213031214143 is an apocalyptic number.

13031214143 is a deficient number, since it is larger than the sum of its proper divisors (389785).

13031214143 is an equidigital number, since it uses as much as digits as its factorization.

13031214143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 389784.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 13031214143 its reverse (34141213031), we get a palindrome (47172427174).

The spelling of 13031214143 in words is "thirteen billion, thirty-one million, two hundred fourteen thousand, one hundred forty-three".

Divisors: 1 36931 352853 13031214143