Base | Representation |
---|---|
bin | 11101101010000011011001… |
… | …001110111100111100011001 |
3 | 122002211021220202201121210120 |
4 | 131222003121032330330121 |
5 | 114044004204110423231 |
6 | 1141224105022103453 |
7 | 36321326400055236 |
oct | 3552033116747431 |
9 | 562737822647716 |
10 | 130433211420441 |
11 | 38618461507336 |
12 | 127669b671ab89 |
13 | 57a1a506c53a7 |
14 | 242d0030c878d |
15 | 1012d019c2d96 |
hex | 76a0d93bcf19 |
130433211420441 has 16 divisors (see below), whose sum is σ = 174888654944640. Its totient is φ = 86466713794560.
The previous prime is 130433211420433. The next prime is 130433211420451. The reversal of 130433211420441 is 144024112334031.
It is a happy number.
It is not a de Polignac number, because 130433211420441 - 23 = 130433211420433 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130433211420451) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5952645 + ... + 17213378.
It is an arithmetic number, because the mean of its divisors is an integer number (10930540934040).
Almost surely, 2130433211420441 is an apocalyptic number.
It is an amenable number.
130433211420441 is a deficient number, since it is larger than the sum of its proper divisors (44455443524199).
130433211420441 is a wasteful number, since it uses less digits than its factorization.
130433211420441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23176576.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 130433211420441 its reverse (144024112334031), we get a palindrome (274457323754472).
The spelling of 130433211420441 in words is "one hundred thirty trillion, four hundred thirty-three billion, two hundred eleven million, four hundred twenty thousand, four hundred forty-one".
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