Base | Representation |
---|---|
bin | 11101101010000100100010… |
… | …000000101000101000100000 |
3 | 122002211102001212020000100212 |
4 | 131222010202000220220200 |
5 | 114044014204143412000 |
6 | 1141224430120033252 |
7 | 36321401554210124 |
oct | 3552044200505040 |
9 | 562742055200325 |
10 | 130434432404000 |
11 | 38618a2874535a |
12 | 12767097602828 |
13 | 57a1bb665587a |
14 | 242d0bb31b584 |
15 | 1012d73ca5c35 |
hex | 76a122028a20 |
130434432404000 has 96 divisors (see below), whose sum is σ = 320484781274112. Its totient is φ = 52172571360000.
The previous prime is 130434432403943. The next prime is 130434432404011. The reversal of 130434432404000 is 404234434031.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 184731635 + ... + 185436365.
It is an arithmetic number, because the mean of its divisors is an integer number (3338383138272).
Almost surely, 2130434432404000 is an apocalyptic number.
130434432404000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130434432404000 is an abundant number, since it is smaller than the sum of its proper divisors (190050348870112).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130434432404000 is an equidigital number, since it uses as much as digits as its factorization.
130434432404000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 751027 (or 751009 counting only the distinct ones).
The product of its (nonzero) digits is 55296, while the sum is 32.
Adding to 130434432404000 its reverse (404234434031), we get a palindrome (130838666838031).
The spelling of 130434432404000 in words is "one hundred thirty trillion, four hundred thirty-four billion, four hundred thirty-two million, four hundred four thousand".
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