130441032014431 has 2 divisors, whose sum is σ = 130441032014432. Its totient is φ = 130441032014430.

The previous prime is 130441032014413. The next prime is 130441032014443. The reversal of 130441032014431 is 134410230144031.

Together with previous prime (130441032014413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (134410230144031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130441032014431 - 2¹³ = 130441032006239 is a prime.

It is a super-2 number, since 2×130441032014431² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130441032014393 and 130441032014402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130441032014131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220516007215 + 65220516007216.

It is an arithmetic number, because the mean of its divisors is an integer number (65220516007216).

Almost surely, 2^{130441032014431} is an apocalyptic number.

130441032014431 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441032014431 is an equidigital number, since it uses as much as digits as its factorization.

130441032014431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 130441032014431 its reverse (134410230144031), we get a palindrome (264851262158462).

The spelling of 130441032014431 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty-two million, fourteen thousand, four hundred thirty-one".