Base | Representation |
---|---|
bin | 11101101010001010101011… |
… | …011000001011000000100001 |
3 | 122002212001002210120020120010 |
4 | 131222022223120023000201 |
5 | 114044121213144120001 |
6 | 1141231441032435133 |
7 | 36322024242055113 |
oct | 3552125330130041 |
9 | 562761083506503 |
10 | 130441032020001 |
11 | 38620804a9155a |
12 | 12768419848aa9 |
13 | 57a26c8a144b1 |
14 | 242d545a133b3 |
15 | 101310d3828d6 |
hex | 76a2ab60b021 |
130441032020001 has 16 divisors (see below), whose sum is σ = 174109198431168. Its totient is φ = 86866779168000.
The previous prime is 130441032019943. The next prime is 130441032020021. The reversal of 130441032020001 is 100020230144031.
It is not a de Polignac number, because 130441032020001 - 213 = 130441032011809 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130441032020001.
It is not an unprimeable number, because it can be changed into a prime (130441032020021) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 263567941 + ... + 264062381.
It is an arithmetic number, because the mean of its divisors is an integer number (10881824901948).
Almost surely, 2130441032020001 is an apocalyptic number.
It is an amenable number.
130441032020001 is a deficient number, since it is larger than the sum of its proper divisors (43668166411167).
130441032020001 is an equidigital number, since it uses as much as digits as its factorization.
130441032020001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 589232.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 130441032020001 its reverse (100020230144031), we get a palindrome (230461262164032).
The spelling of 130441032020001 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty-two million, twenty thousand, one".
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