Base | Representation |
---|---|
bin | 111100101111100000… |
… | …0100101111111110010 |
3 | 110110200210112111010212 |
4 | 1321133000211333302 |
5 | 4114121402310114 |
6 | 135531422224122 |
7 | 12265333201541 |
oct | 1713700457762 |
9 | 413623474125 |
10 | 130443010034 |
11 | 50358751127 |
12 | 21345125042 |
13 | c3ba8c4a4c |
14 | 6456268158 |
15 | 35d6bc0b3e |
hex | 1e5f025ff2 |
130443010034 has 4 divisors (see below), whose sum is σ = 195664515054. Its totient is φ = 65221505016.
The previous prime is 130443010031. The next prime is 130443010079. The reversal of 130443010034 is 430010344031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 430010344031 = 3929 ⋅109445239.
It can be written as a sum of positive squares in only one way, i.e., 69234765625 + 61208244409 = 263125^2 + 247403^2 .
It is a junction number, because it is equal to n+sod(n) for n = 130443009991 and 130443010009.
It is not an unprimeable number, because it can be changed into a prime (130443010031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32610752507 + ... + 32610752510.
Almost surely, 2130443010034 is an apocalyptic number.
130443010034 is a deficient number, since it is larger than the sum of its proper divisors (65221505020).
130443010034 is an equidigital number, since it uses as much as digits as its factorization.
130443010034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65221505019.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 130443010034 its reverse (430010344031), we get a palindrome (560453354065).
The spelling of 130443010034 in words is "one hundred thirty billion, four hundred forty-three million, ten thousand, thirty-four".
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