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130443023041 is a prime number
BaseRepresentation
bin111100101111100000…
…0101001001011000001
3110110200210120010222121
41321133000221023001
54114121403214131
6135531422404241
712265333254502
oct1713700511301
9413623503877
10130443023041
115035875a981
1221345130681
13c3ba8ca946
14645626cba9
1535d6bc4911
hex1e5f0292c1

130443023041 has 2 divisors, whose sum is σ = 130443023042. Its totient is φ = 130443023040.

The previous prime is 130443023023. The next prime is 130443023047. The reversal of 130443023041 is 140320344031.

Adding to 130443023041 its reverse (140320344031), we get a palindrome (270763367072).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121532418225 + 8910604816 = 348615^2 + 94396^2 .

It is a cyclic number.

It is not a de Polignac number, because 130443023041 - 215 = 130442990273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130443022997 and 130443023015.

It is not a weakly prime, because it can be changed into another prime (130443023047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221511520 + 65221511521.

It is an arithmetic number, because the mean of its divisors is an integer number (65221511521).

Almost surely, 2130443023041 is an apocalyptic number.

It is an amenable number.

130443023041 is a deficient number, since it is larger than the sum of its proper divisors (1).

130443023041 is an equidigital number, since it uses as much as digits as its factorization.

130443023041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

The spelling of 130443023041 in words is "one hundred thirty billion, four hundred forty-three million, twenty-three thousand, forty-one".