Base | Representation |
---|---|
bin | 111100110010101101… |
… | …0011011000001100111 |
3 | 110110222021200201000122 |
4 | 1321211122123001213 |
5 | 4114331403203020 |
6 | 135550221032155 |
7 | 12301106315516 |
oct | 1714532330147 |
9 | 413867621018 |
10 | 130550444135 |
11 | 5040335aa41 |
12 | 213750b565b |
13 | c406c3c217 |
14 | 646663267d |
15 | 35e1343125 |
hex | 1e6569b067 |
130550444135 has 4 divisors (see below), whose sum is σ = 156660532968. Its totient is φ = 104440355304.
The previous prime is 130550444071. The next prime is 130550444149. The reversal of 130550444135 is 531444055031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 531444055031 = 163027 ⋅3259853.
It is a cyclic number.
It is not a de Polignac number, because 130550444135 - 26 = 130550444071 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130550444095 and 130550444104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13055044409 + ... + 13055044418.
It is an arithmetic number, because the mean of its divisors is an integer number (39165133242).
Almost surely, 2130550444135 is an apocalyptic number.
130550444135 is a deficient number, since it is larger than the sum of its proper divisors (26110088833).
130550444135 is an equidigital number, since it uses as much as digits as its factorization.
130550444135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26110088832.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 130550444135 its reverse (531444055031), we get a palindrome (661994499166).
The spelling of 130550444135 in words is "one hundred thirty billion, five hundred fifty million, four hundred forty-four thousand, one hundred thirty-five".
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