Base | Representation |
---|---|
bin | 10011000001110111011… |
… | …101110101011111010001 |
3 | 11122000100002000201221021 |
4 | 103001313131311133101 |
5 | 132411104114233303 |
6 | 2440423131555441 |
7 | 163322250505102 |
oct | 23016735653721 |
9 | 4560302021837 |
10 | 1307674367953 |
11 | 4646440a9448 |
12 | 1915295bbb81 |
13 | 9640c036975 |
14 | 474128ca3a9 |
15 | 24037a4bebd |
hex | 130777757d1 |
1307674367953 has 2 divisors, whose sum is σ = 1307674367954. Its totient is φ = 1307674367952.
The previous prime is 1307674367941. The next prime is 1307674368043. The reversal of 1307674367953 is 3597634767031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1290661861329 + 17012506624 = 1136073^2 + 130432^2 .
It is a cyclic number.
It is not a de Polignac number, because 1307674367953 - 25 = 1307674367921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1307674367891 and 1307674367900.
It is not a weakly prime, because it can be changed into another prime (1307674367903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 653837183976 + 653837183977.
It is an arithmetic number, because the mean of its divisors is an integer number (653837183977).
Almost surely, 21307674367953 is an apocalyptic number.
It is an amenable number.
1307674367953 is a deficient number, since it is larger than the sum of its proper divisors (1).
1307674367953 is an equidigital number, since it uses as much as digits as its factorization.
1307674367953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60011280, while the sum is 61.
The spelling of 1307674367953 in words is "one trillion, three hundred seven billion, six hundred seventy-four million, three hundred sixty-seven thousand, nine hundred fifty-three".
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