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13104331307107 is a prime number
BaseRepresentation
bin1011111010110001011100…
…0000110011100001100011
31201101202120101021001212221
42332230113000303201203
53204200132303311412
643512014030331511
72521520355154405
oct276542700634143
951352511231787
1013104331307107
1141a2574436a47
12157785a059b97
1374096b929271
143343783dcb75
1517ad18c8bb07
hexbeb17033863

13104331307107 has 2 divisors, whose sum is σ = 13104331307108. Its totient is φ = 13104331307106.

The previous prime is 13104331307101. The next prime is 13104331307129. The reversal of 13104331307107 is 70170313340131.

13104331307107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13104331307107 - 215 = 13104331274339 is a prime.

It is not a weakly prime, because it can be changed into another prime (13104331307101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552165653553 + 6552165653554.

It is an arithmetic number, because the mean of its divisors is an integer number (6552165653554).

Almost surely, 213104331307107 is an apocalyptic number.

13104331307107 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104331307107 is an equidigital number, since it uses as much as digits as its factorization.

13104331307107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15876, while the sum is 34.

Adding to 13104331307107 its reverse (70170313340131), we get a palindrome (83274644647238).

The spelling of 13104331307107 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, three hundred seven thousand, one hundred seven".