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13104331315277 is a prime number
BaseRepresentation
bin1011111010110001011100…
…0000110101100001001101
31201101202120101021111002112
42332230113000311201031
53204200132304042102
643512014030433405
72521520355220256
oct276542700654115
951352511244075
1013104331315277
1141a25744420a4
12157785a062865
1374096b92cbb7
14334378401b2d
1517ad18c8e252
hexbeb1703584d

13104331315277 has 2 divisors, whose sum is σ = 13104331315278. Its totient is φ = 13104331315276.

The previous prime is 13104331315267. The next prime is 13104331315291. The reversal of 13104331315277 is 77251313340131.

13104331315277 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8256852828676 + 4847478486601 = 2873474^2 + 2201699^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104331315277 - 26 = 13104331315213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104331315267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552165657638 + 6552165657639.

It is an arithmetic number, because the mean of its divisors is an integer number (6552165657639).

Almost surely, 213104331315277 is an apocalyptic number.

It is an amenable number.

13104331315277 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104331315277 is an equidigital number, since it uses as much as digits as its factorization.

13104331315277 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 158760, while the sum is 41.

The spelling of 13104331315277 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, three hundred fifteen thousand, two hundred seventy-seven".