Base | Representation |
---|---|
bin | 1011111010110001011100… |
… | …0000110101100001011010 |
3 | 1201101202120101021111010000 |
4 | 2332230113000311201122 |
5 | 3204200132304042130 |
6 | 43512014030433430 |
7 | 2521520355220305 |
oct | 276542700654132 |
9 | 51352511244100 |
10 | 13104331315290 |
11 | 41a2574442106 |
12 | 157785a062876 |
13 | 74096b92cbc7 |
14 | 334378401b3c |
15 | 17ad18c8e260 |
hex | beb1703585a |
13104331315290 has 80 divisors (see below), whose sum is σ = 35239633811712. Its totient is φ = 3494136985056.
The previous prime is 13104331315277. The next prime is 13104331315291. The reversal of 13104331315290 is 9251313340131.
13104331315290 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 4 + 331 + 31 + 5 + 290 = 666.
13104331315290 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (13104331315291) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 7297327 + ... + 8914013.
Almost surely, 213104331315290 is an apocalyptic number.
13104331315290 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13104331315290 is an abundant number, since it is smaller than the sum of its proper divisors (22135302496422).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13104331315290 is a wasteful number, since it uses less digits than its factorization.
13104331315290 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1626713 (or 1626704 counting only the distinct ones).
The product of its (nonzero) digits is 29160, while the sum is 36.
The spelling of 13104331315290 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, three hundred fifteen thousand, two hundred ninety".
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