131044111151 has 2 divisors, whose sum is σ = 131044111152. Its totient is φ = 131044111150.

The previous prime is 131044111141. The next prime is 131044111157. The reversal of 131044111151 is 151111440131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131044111151 - 2¹⁸ = 131043849007 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131044111157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522055575 + 65522055576.

It is an arithmetic number, because the mean of its divisors is an integer number (65522055576).

Almost surely, 2^131044111151 is an apocalyptic number.

131044111151 is a deficient number, since it is larger than the sum of its proper divisors (1).

131044111151 is an equidigital number, since it uses as much as digits as its factorization.

131044111151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 23.

Adding to 131044111151 its reverse (151111440131), we get a palindrome (282155551282).

The spelling of 131044111151 in words is "one hundred thirty-one billion, forty-four million, one hundred eleven thousand, one hundred fifty-one".