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1311101011117 is a prime number
BaseRepresentation
bin10011000101000011101…
…101011100010010101101
311122100011212212020200001
4103011003231130102231
5132440113324323432
62442151140504301
7163503206500312
oct23050355342255
94570155766601
101311101011117
11466042382147
121921250ab091
1396836c2a881
1447659a30d09
15241887b89e7
hex13143b5c4ad

1311101011117 has 2 divisors, whose sum is σ = 1311101011118. Its totient is φ = 1311101011116.

The previous prime is 1311101011067. The next prime is 1311101011133. The reversal of 1311101011117 is 7111101011131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1083277129636 + 227823881481 = 1040806^2 + 477309^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311101011117 - 211 = 1311101009069 is a prime.

It is a super-2 number, since 2×13111010111172 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311101011094 and 1311101011103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311101011177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655550505558 + 655550505559.

It is an arithmetic number, because the mean of its divisors is an integer number (655550505559).

Almost surely, 21311101011117 is an apocalyptic number.

It is an amenable number.

1311101011117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311101011117 is an equidigital number, since it uses as much as digits as its factorization.

1311101011117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21, while the sum is 19.

Adding to 1311101011117 its reverse (7111101011131), we get a palindrome (8422202022248).

The spelling of 1311101011117 in words is "one trillion, three hundred eleven billion, one hundred one million, eleven thousand, one hundred seventeen".