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131120312350550 = 25211632254863497
BaseRepresentation
bin11101110100000011010011…
…101000111111011101010110
3122012020222110000100101011012
4131310003103220333131112
5114141233344430204200
61142511501231412222
736422062400442065
oct3564032350773526
9565228400311135
10131120312350550
11388628a3027896
1212857bb3384072
13582179166b5a3
1424543852181dc
151025b18413a35
hex7740d3a3f756

131120312350550 has 24 divisors (see below), whose sum is σ = 244093483385496. Its totient is φ = 52403027647040.

The previous prime is 131120312350541. The next prime is 131120312350583. The reversal of 131120312350550 is 55053213021131.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1127373599 + ... + 1127489898.

It is an arithmetic number, because the mean of its divisors is an integer number (10170561807729).

Almost surely, 2131120312350550 is an apocalyptic number.

131120312350550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131120312350550 is a deficient number, since it is larger than the sum of its proper divisors (112973171034946).

131120312350550 is a wasteful number, since it uses less digits than its factorization.

131120312350550 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2254864672 (or 2254864667 counting only the distinct ones).

The product of its (nonzero) digits is 13500, while the sum is 32.

Adding to 131120312350550 its reverse (55053213021131), we get a palindrome (186173525371681).

The spelling of 131120312350550 in words is "one hundred thirty-one trillion, one hundred twenty billion, three hundred twelve million, three hundred fifty thousand, five hundred fifty".

Divisors: 1 2 5 10 25 50 1163 2326 5815 11630 29075 58150 2254863497 4509726994 11274317485 22548634970 56371587425 112743174850 2622406247011 5244812494022 13112031235055 26224062470110 65560156175275 131120312350550