Base | Representation |
---|---|
bin | 111101000011101111… |
… | …1100111111100101101 |
3 | 110112110010121121001221 |
4 | 1322013133213330231 |
5 | 4122014242430013 |
6 | 140123044303341 |
7 | 12321221410033 |
oct | 1720737477455 |
9 | 415403547057 |
10 | 131122233133 |
11 | 5067709a531 |
12 | 214b46a1b51 |
13 | c49853b1c8 |
14 | 64bc554553 |
15 | 362663c08d |
hex | 1e877e7f2d |
131122233133 has 2 divisors, whose sum is σ = 131122233134. Its totient is φ = 131122233132.
The previous prime is 131122233107. The next prime is 131122233149. The reversal of 131122233133 is 331332221131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 114029808489 + 17092424644 = 337683^2 + 130738^2 .
It is a cyclic number.
It is not a de Polignac number, because 131122233133 - 225 = 131088678701 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131122233098 and 131122233107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131122533133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65561116566 + 65561116567.
It is an arithmetic number, because the mean of its divisors is an integer number (65561116567).
Almost surely, 2131122233133 is an apocalyptic number.
It is an amenable number.
131122233133 is a deficient number, since it is larger than the sum of its proper divisors (1).
131122233133 is an equidigital number, since it uses as much as digits as its factorization.
131122233133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1944, while the sum is 25.
Adding to 131122233133 its reverse (331332221131), we get a palindrome (462454454264).
The spelling of 131122233133 in words is "one hundred thirty-one billion, one hundred twenty-two million, two hundred thirty-three thousand, one hundred thirty-three".
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