Search a number
-
+
13112330310097 is a prime number
BaseRepresentation
bin1011111011001111001111…
…0010100101000111010001
31201102112012211210112010221
42332303303302211013101
53204313023024410342
643515415452553041
72522222524443004
oct276636362450721
951375184715127
1013112330310097
1141a59a9693317
121579310a82781
13741644bb0625
143348d68c753b
1517b13613ba67
hexbecf3ca51d1

13112330310097 has 2 divisors, whose sum is σ = 13112330310098. Its totient is φ = 13112330310096.

The previous prime is 13112330310089. The next prime is 13112330310151. The reversal of 13112330310097 is 79001303321131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12676170450321 + 436159859776 = 3560361^2 + 660424^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112330310097 - 23 = 13112330310089 is a prime.

It is a super-3 number, since 3×131123303100973 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (13112330310697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556165155048 + 6556165155049.

It is an arithmetic number, because the mean of its divisors is an integer number (6556165155049).

Almost surely, 213112330310097 is an apocalyptic number.

It is an amenable number.

13112330310097 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112330310097 is an equidigital number, since it uses as much as digits as its factorization.

13112330310097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10206, while the sum is 34.

The spelling of 13112330310097 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty million, three hundred ten thousand, ninety-seven".