Base | Representation |
---|---|
bin | 1011111011001111001111… |
… | …0010100101001000000111 |
3 | 1201102112012211210112012221 |
4 | 2332303303302211020013 |
5 | 3204313023024411101 |
6 | 43515415452553211 |
7 | 2522222524443112 |
oct | 276636362451007 |
9 | 51375184715187 |
10 | 13112330310151 |
11 | 41a59a9693366 |
12 | 1579310a82807 |
13 | 741644bb0667 |
14 | 3348d68c7579 |
15 | 17b13613baa1 |
hex | becf3ca5207 |
13112330310151 has 2 divisors, whose sum is σ = 13112330310152. Its totient is φ = 13112330310150.
The previous prime is 13112330310097. The next prime is 13112330310223. The reversal of 13112330310151 is 15101303321131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13112330310151 - 215 = 13112330277383 is a prime.
It is a super-3 number, since 3×131123303101513 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112330710151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556165155075 + 6556165155076.
It is an arithmetic number, because the mean of its divisors is an integer number (6556165155076).
Almost surely, 213112330310151 is an apocalyptic number.
13112330310151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112330310151 is an equidigital number, since it uses as much as digits as its factorization.
13112330310151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 25.
Adding to 13112330310151 its reverse (15101303321131), we get a palindrome (28213633631282).
The spelling of 13112330310151 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty million, three hundred ten thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •