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13112330310151 is a prime number
BaseRepresentation
bin1011111011001111001111…
…0010100101001000000111
31201102112012211210112012221
42332303303302211020013
53204313023024411101
643515415452553211
72522222524443112
oct276636362451007
951375184715187
1013112330310151
1141a59a9693366
121579310a82807
13741644bb0667
143348d68c7579
1517b13613baa1
hexbecf3ca5207

13112330310151 has 2 divisors, whose sum is σ = 13112330310152. Its totient is φ = 13112330310150.

The previous prime is 13112330310097. The next prime is 13112330310223. The reversal of 13112330310151 is 15101303321131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13112330310151 - 215 = 13112330277383 is a prime.

It is a super-3 number, since 3×131123303101513 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112330710151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556165155075 + 6556165155076.

It is an arithmetic number, because the mean of its divisors is an integer number (6556165155076).

Almost surely, 213112330310151 is an apocalyptic number.

13112330310151 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112330310151 is an equidigital number, since it uses as much as digits as its factorization.

13112330310151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 810, while the sum is 25.

Adding to 13112330310151 its reverse (15101303321131), we get a palindrome (28213633631282).

The spelling of 13112330310151 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty million, three hundred ten thousand, one hundred fifty-one".