Base | Representation |
---|---|
bin | 100111000101001… |
… | …0000000010110000 |
3 | 10101101110110011001 |
4 | 1032022100002300 |
5 | 10141143410000 |
6 | 334041531344 |
7 | 44331644140 |
oct | 11612200260 |
9 | 3341413131 |
10 | 1311310000 |
11 | 613222680 |
12 | 3071a3b54 |
13 | 17b897ba0 |
14 | c6226920 |
15 | 7a1c646a |
hex | 4e2900b0 |
1311310000 has 400 divisors, whose sum is σ = 4295225088. Its totient is φ = 374400000.
The previous prime is 1311309959. The next prime is 1311310031. The reversal of 1311310000 is 131131.
It is a tau number, because it is divible by the number of its divisors (400).
It is a super-2 number, since 2×13113100002 = 3439067832200000000, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (10).
It is an unprimeable number.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 10009935 + ... + 10010065.
Almost surely, 21311310000 is an apocalyptic number.
1311310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1311310000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2147612544).
1311310000 is an abundant number, since it is smaller than the sum of its proper divisors (2983915088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311310000 is a wasteful number, since it uses less digits than its factorization.
1311310000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 190 (or 169 counting only the distinct ones).
The product of its (nonzero) digits is 9, while the sum is 10.
The square root of 1311310000 is about 36212.0145807990. The cubic root of 1311310000 is about 1094.5487879155.
Adding to 1311310000 its reverse (131131), we get a palindrome (1311441131).
Multiplying 1311310000 by its reverse (131131), we get a square (171953391610000 = 131131002).
1311310000 divided by its reverse (131131) gives a 4-th power (10000 = 104).
It can be divided in two parts, 131 and 1310000, that multiplied together give a square (171610000 = 131002).
The spelling of 1311310000 in words is "one billion, three hundred eleven million, three hundred ten thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.243 sec. • engine limits •