Base | Representation |
---|---|
bin | 11101110100010111100110… |
… | …010111000001011110011111 |
3 | 122012100001200111222211121202 |
4 | 131310113212113001132133 |
5 | 114142113010404300212 |
6 | 1142525503303150115 |
7 | 36423463344124163 |
oct | 3564274627013637 |
9 | 565301614884552 |
10 | 131142101243807 |
11 | 38871064314895 |
12 | 1286027444533b |
13 | 5823854847a34 |
14 | 2455450d24ca3 |
15 | 10264912420c2 |
hex | 7745e65c179f |
131142101243807 has 2 divisors, whose sum is σ = 131142101243808. Its totient is φ = 131142101243806.
The previous prime is 131142101243801. The next prime is 131142101243851. The reversal of 131142101243807 is 708342101241131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131142101243807 - 216 = 131142101178271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131142101243801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571050621903 + 65571050621904.
It is an arithmetic number, because the mean of its divisors is an integer number (65571050621904).
Almost surely, 2131142101243807 is an apocalyptic number.
131142101243807 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142101243807 is an equidigital number, since it uses as much as digits as its factorization.
131142101243807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 38.
Adding to 131142101243807 its reverse (708342101241131), we get a palindrome (839484202484938).
The spelling of 131142101243807 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred one million, two hundred forty-three thousand, eight hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •