Base | Representation |
---|---|
bin | 11101110100010111100110… |
… | …011101101110010101011011 |
3 | 122012100001200122022002020011 |
4 | 131310113212131232111123 |
5 | 114142113011332003121 |
6 | 1142525503404542351 |
7 | 36423463365061366 |
oct | 3564274635562533 |
9 | 565301618262204 |
10 | 131142103000411 |
11 | 38871065304628 |
12 | 12860274b519b7 |
13 | 5823855011449 |
14 | 24554512610dd |
15 | 102649148c7e1 |
hex | 7745e676e55b |
131142103000411 has 2 divisors, whose sum is σ = 131142103000412. Its totient is φ = 131142103000410.
The previous prime is 131142103000393. The next prime is 131142103000423. The reversal of 131142103000411 is 114000301241131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131142103000411 - 215 = 131142102967643 is a prime.
It is not a weakly prime, because it can be changed into another prime (131142103000481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571051500205 + 65571051500206.
It is an arithmetic number, because the mean of its divisors is an integer number (65571051500206).
Almost surely, 2131142103000411 is an apocalyptic number.
131142103000411 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142103000411 is an equidigital number, since it uses as much as digits as its factorization.
131142103000411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 131142103000411 its reverse (114000301241131), we get a palindrome (245142404241542).
The spelling of 131142103000411 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred three million, four hundred eleven", and thus it is an aban number.
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