131142103000481 has 2 divisors, whose sum is σ = 131142103000482. Its totient is φ = 131142103000480.

The previous prime is 131142103000423. The next prime is 131142103000483. The reversal of 131142103000481 is 184000301241131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72707682534400 + 58434420466081 = 8526880^2 + 7644241^2 .

It is a cyclic number.

It is not a de Polignac number, because 131142103000481 - 2²² = 131142098806177 is a prime.

It is a super-2 number, since 2×131142103000481² (a number of 29 digits) contains 22 as substring.

Together with 131142103000483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131142103000483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571051500240 + 65571051500241.

It is an arithmetic number, because the mean of its divisors is an integer number (65571051500241).

Almost surely, 2^{131142103000481} is an apocalyptic number.

It is an amenable number.

131142103000481 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142103000481 is an equidigital number, since it uses as much as digits as its factorization.

131142103000481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 29.

The spelling of 131142103000481 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred three million, four hundred eighty-one", and thus it is an aban number.