Search a number
BaseRepresentation
bin11101110100010111100110…
…011111000001011111001001
3122012100001200122221101102121
4131310113212133001133021
5114142113011423403001
61142525503420131241
736423463401010354
oct3564274637013711
9565301618841377
10131142103341001
1138871065517505
1212860275096b21
13582385510048c
14245545130d29b
1510264915086a1
hex7745e67c17c9

131142103341001 has 2 divisors, whose sum is σ = 131142103341002. Its totient is φ = 131142103341000.

The previous prime is 131142103340959. The next prime is 131142103341059. The reversal of 131142103341001 is 100143301241131.

Adding to 131142103341001 its reverse (100143301241131), we get a palindrome (231285404582132).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103763559873600 + 27378543467401 = 10186440^2 + 5232451^2 .

It is a cyclic number.

It is not a de Polignac number, because 131142103341001 - 225 = 131142069786569 is a prime.

It is a super-3 number, since 3×1311421033410013 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (131142103341101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571051670500 + 65571051670501.

It is an arithmetic number, because the mean of its divisors is an integer number (65571051670501).

Almost surely, 2131142103341001 is an apocalyptic number.

It is an amenable number.

131142103341001 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142103341001 is an equidigital number, since it uses as much as digits as its factorization.

131142103341001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 25.

The spelling of 131142103341001 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred three million, three hundred forty-one thousand, one".