1311422551511 has 2 divisors, whose sum is σ = 1311422551512. Its totient is φ = 1311422551510.

The previous prime is 1311422551421. The next prime is 1311422551519. The reversal of 1311422551511 is 1151552241131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1311422551511 - 2¹⁴ = 1311422535127 is a prime.

It is a super-3 number, since 3×1311422551511³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311422551519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711275755 + 655711275756.

It is an arithmetic number, because the mean of its divisors is an integer number (655711275756).

Almost surely, 2^{1311422551511} is an apocalyptic number.

1311422551511 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311422551511 is an equidigital number, since it uses as much as digits as its factorization.

1311422551511 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6000, while the sum is 32.

Adding to 1311422551511 its reverse (1151552241131), we get a palindrome (2462974792642).

The spelling of 1311422551511 in words is "one trillion, three hundred eleven billion, four hundred twenty-two million, five hundred fifty-one thousand, five hundred eleven".