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13119983 is a prime number
BaseRepresentation
bin110010000011…
…000111101111
3220200120020022
4302003013233
511324314413
61145112355
7216342452
oct62030757
926616208
1013119983
117451268
1244886bb
132944a06
141a57499
151242608
hexc831ef

13119983 has 2 divisors, whose sum is σ = 13119984. Its totient is φ = 13119982.

The previous prime is 13119979. The next prime is 13120057. The reversal of 13119983 is 38991131.

It is a weak prime.

It is an emirp because it is prime and its reverse (38991131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13119983 - 22 = 13119979 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13119943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6559991 + 6559992.

It is an arithmetic number, because the mean of its divisors is an integer number (6559992).

Almost surely, 213119983 is an apocalyptic number.

13119983 is a deficient number, since it is larger than the sum of its proper divisors (1).

13119983 is an equidigital number, since it uses as much as digits as its factorization.

13119983 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5832, while the sum is 35.

The square root of 13119983 is about 3622.1517085843. The cubic root of 13119983 is about 235.8546397306.

The spelling of 13119983 in words is "thirteen million, one hundred nineteen thousand, nine hundred eighty-three".