Base | Representation |
---|---|
bin | 10011000101111001010… |
… | …011101000000011000101 |
3 | 11122102111112212110000111 |
4 | 103011321103220003011 |
5 | 132443434023310224 |
6 | 2442420301513021 |
7 | 163534405543561 |
oct | 23057123500305 |
9 | 4572445773014 |
10 | 1312000213189 |
11 | 466463a09a56 |
12 | 192336272771 |
13 | 9694b304cc3 |
14 | 477032206a1 |
15 | 241dc6d8d94 |
hex | 131794e80c5 |
1312000213189 has 2 divisors, whose sum is σ = 1312000213190. Its totient is φ = 1312000213188.
The previous prime is 1312000213129. The next prime is 1312000213201. The reversal of 1312000213189 is 9813120002131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1089867097089 + 222133116100 = 1043967^2 + 471310^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312000213189 - 223 = 1311991824581 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1312000213189.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312000213129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656000106594 + 656000106595.
It is an arithmetic number, because the mean of its divisors is an integer number (656000106595).
Almost surely, 21312000213189 is an apocalyptic number.
It is an amenable number.
1312000213189 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312000213189 is an equidigital number, since it uses as much as digits as its factorization.
1312000213189 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 31.
The spelling of 1312000213189 in words is "one trillion, three hundred twelve billion, two hundred thirteen thousand, one hundred eighty-nine".
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