Base | Representation |
---|---|
bin | 11101110101001101110011… |
… | …010010000111110011101000 |
3 | 122012112121220111110010210201 |
4 | 131311031303102013303220 |
5 | 114144041203312340240 |
6 | 1143012330311121544 |
7 | 36430623513331003 |
oct | 3565156322076350 |
9 | 565477814403721 |
10 | 131200300121320 |
11 | 3889380a040971 |
12 | 1286b5b70732b4 |
13 | 582919b0b0c71 |
14 | 24581b24cc53a |
15 | 1027c4a7b8d9a |
hex | 775373487ce8 |
131200300121320 has 64 divisors (see below), whose sum is σ = 308803656407040. Its totient is φ = 50073192576000.
The previous prime is 131200300121179. The next prime is 131200300121399. The reversal of 131200300121320 is 23121003002131.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 177447816 + ... + 178185655.
It is an arithmetic number, because the mean of its divisors is an integer number (4825057131360).
Almost surely, 2131200300121320 is an apocalyptic number.
131200300121320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131200300121320 is an abundant number, since it is smaller than the sum of its proper divisors (177603356285720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131200300121320 is a wasteful number, since it uses less digits than its factorization.
131200300121320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 355633906 (or 355633902 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 131200300121320 its reverse (23121003002131), we get a palindrome (154321303123451).
The spelling of 131200300121320 in words is "one hundred thirty-one trillion, two hundred billion, three hundred million, one hundred twenty-one thousand, three hundred twenty".
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