131201001210113 has 4 divisors (see below), whose sum is σ = 131287147633968. Its totient is φ = 131114854786260.

The previous prime is 131201001210107. The next prime is 131201001210131. The reversal of 131201001210113 is 311012100102131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131201001210113 - 2¹² = 131201001206017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131201001210091 and 131201001210100.

It is not an unprimeable number, because it can be changed into a prime (131201001210413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43073209643 + ... + 43073212688.

It is an arithmetic number, because the mean of its divisors is an integer number (32821786908492).

Almost surely, 2^{131201001210113} is an apocalyptic number.

It is an amenable number.

131201001210113 is a deficient number, since it is larger than the sum of its proper divisors (86146423855).

131201001210113 is an equidigital number, since it uses as much as digits as its factorization.

131201001210113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 86146423854.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 131201001210113 its reverse (311012100102131), we get a palindrome (442213101312244).

The spelling of 131201001210113 in words is "one hundred thirty-one trillion, two hundred one billion, one million, two hundred ten thousand, one hundred thirteen".