Search a number
-
+
131201321132000 = 2553710369451901
BaseRepresentation
bin11101110101001110110000…
…001000111101111111100000
3122012112201112122122212011002
4131311032300020331333200
5114144100301202211000
61143013015503011132
736430661021640350
oct3565166010757740
9565481478585132
10131201321132000
1138894193405349
121286b840b99aa8
1358293017965b2
14245826bd48b60
151027caa24a8d5
hex7753b023dfe0

131201321132000 has 192 divisors, whose sum is σ = 368449655333760. Its totient is φ = 44978872320000.

The previous prime is 131201321131981. The next prime is 131201321132017. The reversal of 131201321132000 is 231123102131.

It is a happy number.

It is a super-2 number, since 2×1312013211320002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 290106050 + ... + 290557950.

It is an arithmetic number, because the mean of its divisors is an integer number (1919008621530).

Almost surely, 2131201321132000 is an apocalyptic number.

131201321132000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131201321132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (184224827666880).

131201321132000 is an abundant number, since it is smaller than the sum of its proper divisors (237248334201760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131201321132000 is a wasteful number, since it uses less digits than its factorization.

131201321132000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 462302 (or 462284 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 131201321132000 its reverse (231123102131), we get a palindrome (131432444234131).

The spelling of 131201321132000 in words is "one hundred thirty-one trillion, two hundred one billion, three hundred twenty-one million, one hundred thirty-two thousand".