Base | Representation |
---|---|
bin | 1011111011101111100111… |
… | …0000010000110000001100 |
3 | 1201110100122110112202122221 |
4 | 2332323321300100300030 |
5 | 3204433322144102200 |
6 | 43523414041345124 |
7 | 2522651054234263 |
oct | 276737160206014 |
9 | 51410573482587 |
10 | 13121020300300 |
11 | 41a9658993600 |
12 | 157ab371981a4 |
13 | 7423cb369973 |
14 | 3350bca815da |
15 | 17b493ecd91a |
hex | beef9c10c0c |
13121020300300 has 108 divisors (see below), whose sum is σ = 31332802653880. Its totient is φ = 4765721875200.
The previous prime is 13121020300229. The next prime is 13121020300303. The reversal of 13121020300300 is 300302012131.
13121020300300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×131210203003002 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13121020300303) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 9762712 + ... + 11025088.
Almost surely, 213121020300300 is an apocalyptic number.
13121020300300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13121020300300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15666401326940).
13121020300300 is an abundant number, since it is smaller than the sum of its proper divisors (18211782353580).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13121020300300 is a wasteful number, since it uses less digits than its factorization.
13121020300300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1263272 (or 1263254 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 13121020300300 its reverse (300302012131), we get a palindrome (13421322312431).
The spelling of 13121020300300 in words is "thirteen trillion, one hundred twenty-one billion, twenty million, three hundred thousand, three hundred".
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