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13121103 = 34373701
BaseRepresentation
bin110010000011…
…011001001111
3220200121202210
4302003121033
511324333403
61145121503
7216345642
oct62033117
926617683
1013121103
117452096
124489293
132945388
141a57a59
151242b03
hexc8364f

13121103 has 4 divisors (see below), whose sum is σ = 17494808. Its totient is φ = 8747400.

The previous prime is 13121099. The next prime is 13121117. The reversal of 13121103 is 30112131.

13121103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13121103 - 22 = 13121099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13121203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2186848 + ... + 2186853.

It is an arithmetic number, because the mean of its divisors is an integer number (4373702).

Almost surely, 213121103 is an apocalyptic number.

13121103 is a deficient number, since it is larger than the sum of its proper divisors (4373705).

13121103 is an equidigital number, since it uses as much as digits as its factorization.

13121103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4373704.

The product of its (nonzero) digits is 18, while the sum is 12.

The square root of 13121103 is about 3622.3063095216. The cubic root of 13121103 is about 235.8613508592.

Adding to 13121103 its reverse (30112131), we get a palindrome (43233234).

It can be divided in two parts, 1312 and 1103, that added together give a triangular number (2415 = T69).

The spelling of 13121103 in words is "thirteen million, one hundred twenty-one thousand, one hundred three".

Divisors: 1 3 4373701 13121103