Base | Representation |
---|---|
bin | 11000011100001010… |
… | …01110010000000001 |
3 | 1020212102202120202122 |
4 | 30032011032100001 |
5 | 203333003331001 |
6 | 10005555454025 |
7 | 643103644316 |
oct | 141605162001 |
9 | 36772676678 |
10 | 13121152001 |
11 | 5623603781 |
12 | 26622b7315 |
13 | 1311510089 |
14 | 8c68a4d0d |
15 | 51bdd3b1b |
hex | 30e14e401 |
13121152001 has 2 divisors, whose sum is σ = 13121152002. Its totient is φ = 13121152000.
The previous prime is 13121151991. The next prime is 13121152049. The reversal of 13121152001 is 10025112131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9733795600 + 3387356401 = 98660^2 + 58201^2 .
It is an emirp because it is prime and its reverse (10025112131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13121152001 - 222 = 13116957697 is a prime.
It is not a weakly prime, because it can be changed into another prime (13121112001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560576000 + 6560576001.
It is an arithmetic number, because the mean of its divisors is an integer number (6560576001).
Almost surely, 213121152001 is an apocalyptic number.
It is an amenable number.
13121152001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121152001 is an equidigital number, since it uses as much as digits as its factorization.
13121152001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 13121152001 its reverse (10025112131), we get a palindrome (23146264132).
The spelling of 13121152001 in words is "thirteen billion, one hundred twenty-one million, one hundred fifty-two thousand, one".
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