13125113 has 2 divisors, whose sum is σ = 13125114. Its totient is φ = 13125112.

The previous prime is 13125109. The next prime is 13125127. The reversal of 13125113 is 31152131.

13125113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10778089 + 2347024 = 3283^2 + 1532^2 .

It is a cyclic number.

It is not a de Polignac number, because 13125113 - 2² = 13125109 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13125091 and 13125100.

It is not a weakly prime, because it can be changed into another prime (13125103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562556 + 6562557.

It is an arithmetic number, because the mean of its divisors is an integer number (6562557).

Almost surely, 2^13125113 is an apocalyptic number.

13125113 is the 1937-th centered heptagonal number.

It is an amenable number.

13125113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125113 is an equidigital number, since it uses as much as digits as its factorization.

13125113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 90, while the sum is 17.

The square root of 13125113 is about 3622.8597819954. The cubic root of 13125113 is about 235.8853759655.

Adding to 13125113 its reverse (31152131), we get a palindrome (44277244).

The spelling of 13125113 in words is "thirteen million, one hundred twenty-five thousand, one hundred thirteen".