Base | Representation |
---|---|
bin | 1011111011111111101001… |
… | …0101110110111101111011 |
3 | 1201110202202110211102212102 |
4 | 2332333322111312331323 |
5 | 3210021131212422301 |
6 | 43525405140534015 |
7 | 2523162535516142 |
oct | 276777225667573 |
9 | 51422673742772 |
10 | 13125325123451 |
11 | 4200467945992 |
12 | 157b9389b130b |
13 | 7429361875b8 |
14 | 3353aa6a2759 |
15 | 17b646db6b6b |
hex | beffa576f7b |
13125325123451 has 2 divisors, whose sum is σ = 13125325123452. Its totient is φ = 13125325123450.
The previous prime is 13125325123441. The next prime is 13125325123507. The reversal of 13125325123451 is 15432152352131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13125325123451 - 218 = 13125324861307 is a prime.
It is not a weakly prime, because it can be changed into another prime (13125325123441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562662561725 + 6562662561726.
It is an arithmetic number, because the mean of its divisors is an integer number (6562662561726).
Almost surely, 213125325123451 is an apocalyptic number.
13125325123451 is a deficient number, since it is larger than the sum of its proper divisors (1).
13125325123451 is an equidigital number, since it uses as much as digits as its factorization.
13125325123451 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 108000, while the sum is 38.
Adding to 13125325123451 its reverse (15432152352131), we get a palindrome (28557477475582).
The spelling of 13125325123451 in words is "thirteen trillion, one hundred twenty-five billion, three hundred twenty-five million, one hundred twenty-three thousand, four hundred fifty-one".
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