13125433543 has 8 divisors (see below), whose sum is σ = 13157813120. Its totient is φ = 13093090560.

The previous prime is 13125433471. The next prime is 13125433547. The reversal of 13125433543 is 34533452131.

13125433543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13125433543 - 2¹³ = 13125425351 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13125433499 and 13125433508.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13125433547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 793663 + ... + 810031.

It is an arithmetic number, because the mean of its divisors is an integer number (1644726640).

Almost surely, 2^13125433543 is an apocalyptic number.

13125433543 is a deficient number, since it is larger than the sum of its proper divisors (32379577).

13125433543 is a wasteful number, since it uses less digits than its factorization.

13125433543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18297.

The product of its digits is 64800, while the sum is 34.

Adding to 13125433543 its reverse (34533452131), we get a palindrome (47658885674).

The spelling of 13125433543 in words is "thirteen billion, one hundred twenty-five million, four hundred thirty-three thousand, five hundred forty-three".