Base | Representation |
---|---|
bin | 11000011101001110… |
… | …00001000110011001 |
3 | 1020220001102200001221 |
4 | 30032213001012121 |
5 | 203342240323113 |
6 | 10010513412041 |
7 | 643242152356 |
oct | 141647010631 |
9 | 36801380057 |
10 | 13130011033 |
11 | 5628604697 |
12 | 266526a021 |
13 | 13132c24c9 |
14 | 8c7b2d62d |
15 | 51ca8398d |
hex | 30e9c1199 |
13130011033 has 4 divisors (see below), whose sum is σ = 13553559808. Its totient is φ = 12706462260.
The previous prime is 13130011019. The next prime is 13130011057. The reversal of 13130011033 is 33011003131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13130011033 - 25 = 13130011001 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13130010998 and 13130011016.
It is not an unprimeable number, because it can be changed into a prime (13130014033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211774341 + ... + 211774402.
It is an arithmetic number, because the mean of its divisors is an integer number (3388389952).
Almost surely, 213130011033 is an apocalyptic number.
It is an amenable number.
13130011033 is a deficient number, since it is larger than the sum of its proper divisors (423548775).
13130011033 is an equidigital number, since it uses as much as digits as its factorization.
13130011033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 423548774.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 13130011033 its reverse (33011003131), we get a palindrome (46141014164).
The spelling of 13130011033 in words is "thirteen billion, one hundred thirty million, eleven thousand, thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •