Base | Representation |
---|---|
bin | 11101110110101101100011… |
… | …010110101101000110111010 |
3 | 122012220110021122022220211020 |
4 | 131312231203112231012322 |
5 | 114202232233144233310 |
6 | 1143131452244443310 |
7 | 36441223343624610 |
oct | 3566554326550672 |
9 | 565813248286736 |
10 | 131303112102330 |
11 | 38923378797a13 |
12 | 1288750a6a9536 |
13 | 5835aa435409c |
14 | 245d166bb16b0 |
15 | 102a766808170 |
hex | 776b635ad1ba |
131303112102330 has 64 divisors (see below), whose sum is σ = 372564495440640. Its totient is φ = 28977238531584.
The previous prime is 131303112102289. The next prime is 131303112102341. The reversal of 131303112102330 is 33201211303131.
It is a self number, because there is not a number n which added to its sum of digits gives 131303112102330.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10780216579 + ... + 10780228758.
It is an arithmetic number, because the mean of its divisors is an integer number (5821320241260).
Almost surely, 2131303112102330 is an apocalyptic number.
131303112102330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131303112102330 is an abundant number, since it is smaller than the sum of its proper divisors (241261383338310).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131303112102330 is a wasteful number, since it uses less digits than its factorization.
131303112102330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21560445383.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 131303112102330 its reverse (33201211303131), we get a palindrome (164504323405461).
The spelling of 131303112102330 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred twelve million, one hundred two thousand, three hundred thirty".
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