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131303122020000 = 2532547179476473
BaseRepresentation
bin11101110110101101100011…
…111100100010011010100000
3122012220110022022222210022100
4131312231203330202122200
5114202232243214120000
61143131453241210400
736441223524132240
oct3566554374423240
9565813268883270
10131303122020000
1138923383351237
1212887511a90a00
135835aa6417328
14245d168233b20
15102a767616a00
hex776b63f226a0

131303122020000 has 1440 divisors, whose sum is σ = 565299316213632. Its totient is φ = 28212535296000.

The previous prime is 131303122019969. The next prime is 131303122020001. The reversal of 131303122020000 is 20221303131.

131303122020000 is a `hidden beast` number, since 1 + 3 + 130 + 312 + 20 + 200 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (1440).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (131303122020001) by changing a digit.

It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 20284736764 + ... + 20284743236.

Almost surely, 2131303122020000 is an apocalyptic number.

131303122020000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131303122020000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (282649658106816).

131303122020000 is an abundant number, since it is smaller than the sum of its proper divisors (433996194193632).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131303122020000 is a wasteful number, since it uses less digits than its factorization.

131303122020000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7480 (or 7454 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 131303122020000 its reverse (20221303131), we get a palindrome (131323343323131).

The spelling of 131303122020000 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred twenty-two million, twenty thousand".