Base | Representation |
---|---|
bin | 1011111100010100110111… |
… | …1101111101000100000010 |
3 | 1201111022110120121011112011 |
4 | 2333011031331331010002 |
5 | 3210114313404013102 |
6 | 43532150404323134 |
7 | 2523453664562041 |
oct | 277051575750402 |
9 | 51438416534464 |
10 | 13131023110402 |
11 | 420292124790a |
12 | 1580a690a34aa |
13 | 7433337cc202 |
14 | 33578b336558 |
15 | 17b87c2442d7 |
hex | bf14df7d102 |
13131023110402 has 4 divisors (see below), whose sum is σ = 19696534665606. Its totient is φ = 6565511555200.
The previous prime is 13131023110369. The next prime is 13131023110423. The reversal of 13131023110402 is 20401132013131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9613714158801 + 3517308951601 = 3100599^2 + 1875449^2 .
It is a super-2 number, since 2×131310231104022 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3282755777599 + ... + 3282755777602.
Almost surely, 213131023110402 is an apocalyptic number.
13131023110402 is a deficient number, since it is larger than the sum of its proper divisors (6565511555204).
13131023110402 is an equidigital number, since it uses as much as digits as its factorization.
13131023110402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6565511555203.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 13131023110402 its reverse (20401132013131), we get a palindrome (33532155123533).
The spelling of 13131023110402 in words is "thirteen trillion, one hundred thirty-one billion, twenty-three million, one hundred ten thousand, four hundred two".
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