13131113100 has 216 divisors, whose sum is σ = 44656048080. Its totient is φ = 2970132480.

The previous prime is 13131113071. The next prime is 13131113111. The reversal of 13131113100 is 131113131.

It is a super-2 number, since 2×13131113100² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13131113100.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 1421296 + ... + 1430504.

Almost surely, 2^13131113100 is an apocalyptic number.

13131113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13131113100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22328024040).

13131113100 is an abundant number, since it is smaller than the sum of its proper divisors (31524934980).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13131113100 is a wasteful number, since it uses less digits than its factorization.

13131113100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9337 (or 9323 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 13131113100 its reverse (131113131), we get a palindrome (13262226231).

The spelling of 13131113100 in words is "thirteen billion, one hundred thirty-one million, one hundred thirteen thousand, one hundred".