Search a number
-
+
131403 = 343801
BaseRepresentation
bin100000000101001011
320200020210
4200011023
513201103
62452203
71055046
oct400513
9220223
10131403
118a7a8
1264063
1347a6c
1435c5d
1528e03
hex2014b

131403 has 4 divisors (see below), whose sum is σ = 175208. Its totient is φ = 87600.

The previous prime is 131381. The next prime is 131413. The reversal of 131403 is 304131.

131403 is nontrivially palindromic in base 11.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304131 = 3101377.

It is not a de Polignac number, because 131403 - 25 = 131371 is a prime.

It is a D-number.

It is a Duffinian number.

It is an inconsummate number, since it does not exist a number n which divided by its sum of digits gives 131403.

It is not an unprimeable number, because it can be changed into a prime (131413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21898 + ... + 21903.

It is an arithmetic number, because the mean of its divisors is an integer number (43802).

2131403 is an apocalyptic number.

131403 is a deficient number, since it is larger than the sum of its proper divisors (43805).

131403 is an equidigital number, since it uses as much as digits as its factorization.

131403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43804.

The product of its (nonzero) digits is 36, while the sum is 12.

The square root of 131403 is about 362.4955172137. The cubic root of 131403 is about 50.8395573018.

Adding to 131403 its reverse (304131), we get a palindrome (435534).

The spelling of 131403 in words is "one hundred thirty-one thousand, four hundred three".

Divisors: 1 3 43801 131403