Base | Representation |
---|---|
bin | 11101111000001010111110… |
… | …111001001101001100001011 |
3 | 122020021001020010010220021221 |
4 | 131320022332321031030023 |
5 | 114210403212110333344 |
6 | 1143245523042542511 |
7 | 36451404355000465 |
oct | 3570127671151413 |
9 | 566231203126257 |
10 | 131403432121099 |
11 | 3896197882a936 |
12 | 128a2a47667a37 |
13 | 58423a1250438 |
14 | 2463d62537135 |
15 | 102d188ba8184 |
hex | 7782bee4d30b |
131403432121099 has 2 divisors, whose sum is σ = 131403432121100. Its totient is φ = 131403432121098.
The previous prime is 131403432121079. The next prime is 131403432121133. The reversal of 131403432121099 is 990121234304131.
It is a weak prime.
It is an emirp because it is prime and its reverse (990121234304131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131403432121099 - 221 = 131403430023947 is a prime.
It is not a weakly prime, because it can be changed into another prime (131403432121079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701716060549 + 65701716060550.
It is an arithmetic number, because the mean of its divisors is an integer number (65701716060550).
Almost surely, 2131403432121099 is an apocalyptic number.
131403432121099 is a deficient number, since it is larger than the sum of its proper divisors (1).
131403432121099 is an equidigital number, since it uses as much as digits as its factorization.
131403432121099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 139968, while the sum is 43.
The spelling of 131403432121099 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred thirty-two million, one hundred twenty-one thousand, ninety-nine".
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