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131404034341 is a prime number
BaseRepresentation
bin111101001100001001…
…0100111000100100101
3110120011202212120122201
41322120102213010211
54123103413044331
6140211032254501
712331212601636
oct1723022470445
9416152776581
10131404034341
1150801173998
1221572b41431
13c511a36698
146507b4b88d
153641253a61
hex1e984a7125

131404034341 has 2 divisors, whose sum is σ = 131404034342. Its totient is φ = 131404034340.

The previous prime is 131404034297. The next prime is 131404034347. The reversal of 131404034341 is 143430404131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126497592225 + 4906442116 = 355665^2 + 70046^2 .

It is a cyclic number.

It is not a de Polignac number, because 131404034341 - 27 = 131404034213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131404034347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65702017170 + 65702017171.

It is an arithmetic number, because the mean of its divisors is an integer number (65702017171).

Almost surely, 2131404034341 is an apocalyptic number.

It is an amenable number.

131404034341 is a deficient number, since it is larger than the sum of its proper divisors (1).

131404034341 is an equidigital number, since it uses as much as digits as its factorization.

131404034341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 131404034341 its reverse (143430404131), we get a palindrome (274834438472).

The spelling of 131404034341 in words is "one hundred thirty-one billion, four hundred four million, thirty-four thousand, three hundred forty-one".