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131421035 = 526284207
BaseRepresentation
bin1111101010101…
…01001101101011
3100011021212202202
413311111031223
5232120433120
621012450415
73154026464
oct765251553
9304255682
10131421035
1168202629
1238019a0b
13212c5535
141364dd6b
15b80e875
hex7d5536b

131421035 has 4 divisors (see below), whose sum is σ = 157705248. Its totient is φ = 105136824.

The previous prime is 131421013. The next prime is 131421053. The reversal of 131421035 is 530124131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131421035 - 224 = 114643819 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131420998 and 131421016.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13142099 + ... + 13142108.

It is an arithmetic number, because the mean of its divisors is an integer number (39426312).

Almost surely, 2131421035 is an apocalyptic number.

131421035 is a deficient number, since it is larger than the sum of its proper divisors (26284213).

131421035 is an equidigital number, since it uses as much as digits as its factorization.

131421035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26284212.

The product of its (nonzero) digits is 360, while the sum is 20.

The square root of 131421035 is about 11463.9013865263. The cubic root of 131421035 is about 508.4188309714.

Adding to 131421035 its reverse (530124131), we get a palindrome (661545166).

The spelling of 131421035 in words is "one hundred thirty-one million, four hundred twenty-one thousand, thirty-five".

Divisors: 1 5 26284207 131421035