Base | Representation |
---|---|
bin | 11101111010001100000101… |
… | …010010010010100110011010 |
3 | 122020202022000210000011212120 |
4 | 131322030011102102212122 |
5 | 114220141110311233300 |
6 | 1143433330125122110 |
7 | 36464412451001001 |
oct | 3572140522224632 |
9 | 566668023004776 |
10 | 131542052055450 |
11 | 38a05742100253 |
12 | 129058930b9336 |
13 | 5852492c2322a |
14 | 246a952761c38 |
15 | 1031a9d6713a0 |
hex | 77a30549299a |
131542052055450 has 48 divisors (see below), whose sum is σ = 328714550895456. Its totient is φ = 34810110462400.
The previous prime is 131542052055431. The next prime is 131542052055457. The reversal of 131542052055450 is 54550250245131.
It is a happy number.
It is a super-2 number, since 2×1315420520554502 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131542052055457) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3347106357 + ... + 3347145656.
It is an arithmetic number, because the mean of its divisors is an integer number (6848219810322).
Almost surely, 2131542052055450 is an apocalyptic number.
131542052055450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131542052055450 is an abundant number, since it is smaller than the sum of its proper divisors (197172498840006).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131542052055450 is a wasteful number, since it uses less digits than its factorization.
131542052055450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6694252159 (or 6694252154 counting only the distinct ones).
The product of its (nonzero) digits is 600000, while the sum is 42.
The spelling of 131542052055450 in words is "one hundred thirty-one trillion, five hundred forty-two billion, fifty-two million, fifty-five thousand, four hundred fifty".
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