Base | Representation |
---|---|
bin | 1011111110001001100010… |
… | …1010001110011100101011 |
3 | 1201121022022011201211221021 |
4 | 2333202120222032130223 |
5 | 3211122433244013003 |
6 | 43554410155353311 |
7 | 2525643036343405 |
oct | 277423052163453 |
9 | 51538264654837 |
10 | 13162341001003 |
11 | 4215132398627 |
12 | 1586b49452837 |
13 | 746284c2451c |
14 | 3370bc7dbb75 |
15 | 17c5b18e42bd |
hex | bf898a8e72b |
13162341001003 has 4 divisors (see below), whose sum is σ = 13163813142928. Its totient is φ = 13160868859080.
The previous prime is 13162341000959. The next prime is 13162341001039. The reversal of 13162341001003 is 30010014326131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13162341001003 - 221 = 13162338903851 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13162341001703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 736057551 + ... + 736075432.
It is an arithmetic number, because the mean of its divisors is an integer number (3290953285732).
Almost surely, 213162341001003 is an apocalyptic number.
13162341001003 is a deficient number, since it is larger than the sum of its proper divisors (1472141925).
13162341001003 is an equidigital number, since it uses as much as digits as its factorization.
13162341001003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1472141924.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13162341001003 its reverse (30010014326131), we get a palindrome (43172355327134).
The spelling of 13162341001003 in words is "thirteen trillion, one hundred sixty-two billion, three hundred forty-one million, one thousand, three".
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